Unprotect[Power];0^0:=1;Protect[Power]; f=(p0*z)^k(1-p0*z)(1-p0*z-q0*z*(1-(p0*z)^k))^(-1); D[f,{z,1}]/.k->1/.z->0 D[f,{z,2}]/2/.k->1/.z->0//Simplify D[f,{z,3}]/6/.k->1/.z->0//Simplify D[f,{z,4}]/24/.k->1/.z->0//Simplify test1=Table[(D[f,{z,n}]/n!/.k->1/.z->0),{n,1,10}]//Simplify SeriesCoefficient[f/.k->1,{z,0,n}] test2=SeriesCoefficient[f/.k->1,{z,0,#}]&/@Range[10]//Simplify test1===test2 mytable[{kl_,ku_},{nl_,nu_}]:= TableForm[Table[SeriesCoefficient[f/.k->kk,{z,0,nn}], {kk,kl,ku},{nn,nl,nu}], TableHeadings->{Range[kl,ku],"第"<>ToString[#]<>"項"&/@Range[nl,nu]}] mytable[{11,20},{8,15}]
Mathematica 教學:級數係數
由 戴忠淵 於 2014年8月12日星期二
下午2:29 發表
讀者回應 ( 0 意見 )
訂閱發佈留言 (Atom)
發佈留言
Please leave your name and tell me what you thought about this site. Comments, suggestions and views are welcomed.
如果這篇文章對你有幫助,那請留個訊息給我~